Qualcomm India Private Limited| 2023,2024|GET

 

Company:

Qualcomm India Private Limited

Job Area:

Engineering Group, Engineering Group > Hardware Engineering

Minimum Qualifications:

• Associate's degree in Computer Science, Electrical/Electronic Engineering, Engineering, or related field.

Must have educational background in one or more of the following areas:

Verifying SoC with embedded RISC/DSP processors, communications/ networking ASICs.
• Verilog or VHDL, C/C++, Tcl/Perl/shell-scripting. RTL design experience and/or strong OO programming knowledge
• Knowledge of wireless/wired communications and protocols or graphics/video multi-media is a plus.
• Knowledge in PLL, LNA, OpAmp, CMOS, ADC/DAC, Cadence, SpectreRF, or Layout is required in RF/Analog/Mixed Signal IC Design.
• Excellent analytical and problem solving skills.
• Ability to collaborate and work in teams.
• Good verbal and written communication skill

Preferred Qualifications:

•    Bachelor's degree in Computer Science, Electrical/Electronic Engineering, Engineering, or related field.

Registration Link : Click Here

Innovaccer | 2019,2020,2021, 2022 and 2023 only.|Data Engineer

Your Role

As an Apprentice- Data Engineer, you will be an integral part of our Data Engineering  team, working towards transforming and analyzing healthcare data to contribute to the enhancement of population health and the reduction of healthcare costs. This role offers a unique opportunity for a self-starter with a passion for data engineering to learn and grow within a dynamic and innovative environment.

What You Need

• B.E/ B. Tech/ M. Tech  in computer science , or related field of batch 2019,2020,2021, 2022 and 2023 only.
• Must be available  for apprenticeship tenure of minimum 1 year.
• Basic understanglading of data modeling concepts.
• Exposure to SQL and the ability to write simple queries.
• Eagerness to learn and work with Python libraries, such as Numpy, Scipy, Scikit-Learn.
• Interest in BI tools like Power BI, Tableau, or Sisense.
• Strong analytical and problem-solving skills.
• Excellent oral and written communication skills.
• Enthusiasm for multitasking and managing multiple tasks simultaneously.

Registration Link: Apply

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Material

Deep Learning

1. Linear Algebra - Scalars, Vectors, Matrices and Tensors

2. Linear Algebra (Matrix operations)

Deep learning  CNN    

Deep Learning Recorded Sessions (UNIT -3) Regularization

#UNIT -2 ( Deep Learning PCA)

#UNIT-3 (Fundamentals of Deep Learning)

#UNIT -3 Regularization (Introduction, Parameter Norm penalties, Constraint based, Under constraint based penalization) 

#UNIT -3  Regularization (Data Augmentation, Noise Robustness)

#UNIT-3   Regularization (Multi Tasking, Early Stopping, Sparse Representation, Bagging and Other Ensemble models)

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Home                                                                                                                        Previous

Internships: 

1. Atlassian Women Tech 3.0 Intern

2.AMD Intern Hiring

3. Infosys Internship

4. Google Internship

Placements:

1. ECLERX Off campus Drive | Data Analyst (AMP Data) 

2. DP Worlds

3. L & T Software 

Material

Deep Learning

1. Linear Algebra - Scalars, Vectors, Matrices and Tensors

2. Linear Algebra (Matrix operations)

Deep learning  CNN    

Accenture Questions and Answers with Explanation

1.  A certain number of men take 45 days to complete work. If there are 10 men less then they will take 60 days to complete the work. Find the original number of men.

 

A.  50

B.  60

C.  30

D.  40

 

Answer – D. 40

Explanation:

Let us assume initially there are X men. Then x*45 = (x-10)*60. So we get x = 40

 

2.  5 men and 10 boys can do a piece of work in 30 days and 8 men and 12 boys can do the work in 20 days then the ratio of daily work done by a man to that of a boy.

 

A. 5:1

B. 4:5

C. 6:1

D. 7:3

 

Answer – C. 6:1

Explanation:

Given that, 5m + 10b = 1/30 and 8m + 12b = 1/20 after solving we get m = 1/200 and b = 1/1200

so required ratio = (1/200) : (1/1200) = 6:1

 

3.  4 women and 5 men working together can do 3 times the work done by 2 women and one man together. Calculate the work of a man to that of a woman.

 

A. 1:1

B. 3:2

C. 1:2

D. 2:1

 

Answer – A. 1:1

Explanation:

Given

4w + 5m = 3*(2w + m)

i.e. 2w = 2m

so the ratio of work done by man to woman is 1:1

 

 

 

 

 

4.  Manoj can do a work in 20 days, while Chandu can do the same work in 25 days. They started the work jointly. A few days later Suresh also joined them and thus all of them completed the whole work in 10 days. All of them were paid total Rs.1000. What is the share of Suresh?

 

A. 100

B. 300

C. 200

D. 400

 

Answer – A. 100

Explanation:

Efficiency of Manoj = 5%

The efficiency of Chandu = 4%

They will complete only 90% of the work = [(5+4)*10] =90 Remaining work was done by Suresh = 10%.

Share of Suresh = 10/100 * 1000 = 100

 

5.  Nagarjuna lends Rs 30,000 of two of his friends. He gives Rs 15,000 to the first at 6% p.a. simple interest. He wants to make a profit of 10% on the whole. The simple interest rate at which he should lend the remaining sum of money to the second friend is

 

A.  8%

B. 12%

C. 14%

D. 16%

 

Answer - C. 14%

Explanation:

Simple Interest on Rs 15000

=(15000×6×1)/100 = Rs. 900

Profit to made on Rs 30000

= 30000×10/100=Rs 3000

Simple Interest on Rs.15000 = 3000-900 = Rs.2100 Rate=(S.I.* 100)/(P * T)=(2100×100)/15000

=14% per annum

Therefore, the simple interest rate at which he should lend the remaining sum of money to the second friend is 14%

 

 

 

 

 

6.  A portion of $6600 is invested at a 5% annual return, while the remainder is invested at a 3% annual return. If the annual income from the portion earning a 5% return is twice that of the other portion, what is the total income from the two investments after one year?

 

A. 270

B. 250

C. 280

D. 200

 

Answer - A. 270

Explanation:

According to the given data 5x + 3y = z (total)

x + y = 6600

5x= 2(3y) [ condition given] 5x – 6y = 0 x + y = 6600

5x -6y = 0

Subtract both equations and you get x = 3600 so y = 3000 3600*.05 = 180

3000*.03 = 90

z (total) = 270

Therefore, the total income from the two investments after one year = 270

 

7.  While calculating the weight of a group of men, the weight of 63 kg of one of the member was mistakenly written as 83 kg. Due to this the average of the weights increased by half kg. What is the number of men in the group?

 

A.  25

B.  20

C.  40

D.  60

 

Answer - C. 40

Explanation:

Increase in marks lead to an increase in average by 1/2 So (83-63) = x/2

x = 40

Therefore, the number of men in the group are 40

 

 

 

 

 

 

8.  In a group of 8 boys, 2 men aged at 21 and 23 were replaced, two new boys. Due to this the average cost of the group increased by 2 years. What is the average age of the 2 new boys?

 

A.  17

B.  30

C.  28

D.  23

 

Answer - B. 30

Explanation:

According to the given data

Average of 8 boys increased by 2, this means the total age of boys increased by 8*2 = 16 yrs

So sum of ages of two new boys = 21+23+16 = 60 Average of these = 60/2 = 30

 

9.  A Boat takes total 16 hours for traveling downstream from point A to point B and coming back point C which is somewhere between A and B. If the speed of the Boat in Still water is 9 Km/hr and the rate of stream is 6 Km/hr, then what is the distance between A and C?

 

A.  60 Km

B.  90 Km

C.  30 Km

D.  Cannot be determined

 

Answer – D. Cannot be determined

Explanation:

16 = D/9+6 + x/9-6

 

10.  A Boat going upstream takes 8 hours 24 minutes to cover a certain distance, while it takes 5 hours to cover 5/7 of the same distance running downstream. Then what is the ratio of the speed of boat to speed of water current?

 

A. 11:5

B. 11:6

C. 11:1

D. 6:5

 

 

 

 

 

 

Answer – C. 11:1

Explanation:

(S-R)*42/5 = (S+R)*7 S:R = 11:1

 

11.  A Boat takes 128 min less to travel to 48 Km downstream than to travel the same distance upstream. If the speed of the stream is 3 Km/hr. Then Speed of Boat in still water is?

 

A.  12 Km/hr

B.  15 Km/hr

C.  6 Km/hr

D.  9 Km/hr

 

Answer – A. 12 Km/hr

Explanation:

32/15 = 48(1/s-3 – 1/s+3) s= 12

Therefore, Speed of Boat in still water is 12 Km/hr.

 

12.  An alloy contains Brass, Iron, and Zinc in the ratio 2:3:1 and another contains Iron, zinc, and lead in the ratio 5:4:3. If equal weights of both alloys are melted together to form a third alloy, then what will be the weight of lead per kg in new alloy?

 

A. 1/4

B. 41/7

C. 1/8

D. 51/9

 

Answer – C. 1/8 Explanation: Shortcut:

In the first alloy, 2:3:1 =6*2

5:4:3 =12

Multiply 2 to make it equal, 4:6:2

5:4:3

Adding all, 4:11:6:3=24

3/24=1/8

 

 

 

 

 

13.  A milkman mixes 6 liters of free tap water with 20litres of pure milk. If the cost of pure milk is Rs.28 per liter the % Profit of the milkman when he sells all the mixture at the cost price is

 

A. 30%

B. 16(1/3)%

C. 25%

D. 16.5%

 

Answer – A. 30%

Explanation:

Profit=28*6=728 Cp=28*20=560

Profit = 168*100/560=30%

 

14.  144 liters of the mixture contains milk and water in the ratio 5: 7. How much milk needs to be added to this mixture so that the new ratio is 23: 21 respectively?

 

A.  40 liters

B.  28 liters

C.  32 liters

D.  36 liters

 

Answer – C. 32 liters

Explanation:

144 == 5:7

60: 84

Now == 21 = 84

23 = 92

92-60 = 32

15.  A shopkeeper bought 30kg of rice at Rs.75 per kg and 20 kg of rice the rate of Rs.70. per kg.If he mixed the two brand of rice and sold the mixture at Rs.80 per kg. Find his gain

 

A.  Rs.350

B.  Rs.550

C.  Rs.420 D.Rs.210

 

Answer – A. Rs.350

 

 

 

 

 

Explanation:

CP = 30*75 + 20*70 = 2250 + 1400

= 3650

SP =80*(30+20) = 4000

Hence, Gain = 4000-3650 = 350

 

16.  Cost price of 80 notebooks is equal to the selling price of 65 notebooks. The gain or loss % is

 

A. 32%

B. 42%

C. 27%

D. 23%

 

Answer – D. 23%

Explanation:

% = [80 – 65/65]*100

= 15*100/65 = 1500/65

= 23.07 = 23% profit

Therefore, the gain percentage is 23%.

 

17.  Eight years ago, Pranathi’s age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ratio between the ages of her daughter and her son that time will be 7:6. If Pranathi’s husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter?

 

A.  19 years

B.  27 years

C.  15 years

D.  23 years

 

Answer – D. 23 years

Explanation:

P – 8 = S + D —(1)

6D + 30 = 7S + 35 —(2) H = 7 + P

H = 3S

3S = 7 + P —-(3)

Solving equation (1),(2) and (3) D = 23

Therefore, the present age of the daughter is 23 years

 

 

 

 

 

18.  Shas married 8 year ago. Today her age is 9/7 times to that time of marriage. At present his son’s age is 1/6th of her age. What was her son’s age 3 year ago?

 

A.  4 yr

B.  2 yr

C.  3 yr

D.  5 yr

 

Answer – B. 2 yr

Explanation:

Let us assume that Sravan’s age 8 year ago = x Present age = x + 8

x + 8 = 9/7 x 7(x + 8)= 9x

x = 28; 28 + 8 = 36

Son’s age = 1/6 * 36 = 6 Son’s age 4 year ago = 6-4 =2

 

19.  The respective ratio between the present age of Mani and Dheeraj is x : 42. Mani is 8 years younger than Murali. Murali’s age after 8 years will be 33 years. The difference between Dheeraj’s and Mani’s age is same as the present age of Murali. What is the value of x?

 

A.  18

B.  10

C.  16

D.  17

 

Answer – D. 17

Explanation:

Murali’s age after 8 years = 33 years Murali’s present age = 33 – 8= 25 years Mani’s present age = 25 – 8 = 17 years Dheeraj’s present age = 17 + 25 = 42 years Ratio between Mani and Dheeraj = 17: 42 X = 17

 

20.  Revanth’s present age is three times his son’s present age and 4/5th of his father’s present age. The average of the present ages of all of them is 62 years. What is the difference between the Revanth’s son’s present age and Revanth’s father’s present age?

 

 

 

 

 

A.  64 years

B.  69 years

C.  66 years

D.  62 years

 

Answer – C. 66 years

Explanation:

Present age of Revanth is = 4/5x

Present age of Revanth’s father is = 4/15x Ratio = 15: 12 : 4

Difference between the Revanth’s son’s present age and Revanth’s father’s present age = 62/31 * 3(15 – 4).

= 2*3*11 = 66 years.

 

21. 36% of 945 – 26% of 765 + 17.7 =?

 

A. 167

B. 187

C. 159

D. 143

 

Answer – C. 159

Explanation:

340.2 – 198.9 =141.3+17.7 = 159

 

22. √(456÷12+142-11) =?

A. 11

B. 169

C. 23

D. 13

 

Answer – D. 13

Explanation:

38+142-11 = 169 = 13*13

 

23. 1(1/5) of 1(1/2) of ? = 216

A. 100

B. 125

C. 140

D. 120

 

 

 

 

Answer – D. 120

 

Explanation:

6/5*3/2 *x = 216

X = 216*2*5/6*3 = 2160/18 = 120 24. 15 32 60 122 240 ?

A. 488

B. 482

C. 364

D. 362

 

Answer – B. 482

Explanation:

15 * 2 + 2 = 32

32 * 2 – 4 = 60

60 * 2 + 2 = 122; 122 * 2 – 4 = 240

Then 240*2 + 2 = 482

 

25. 18 10 8 9 11.5 ?

 

A. 10.75

B. 18.75

C. 19.75

D. 14.75

 

Answer – D. 14.75

Explanation:

18 / 2 + 1 = 10

10 / 2 + 3 = 8

8 / 2 + 5 = 9

9 / 2 + 7 = 11.5

11.5 / 2 + 9 = 14.75